180=0.05s^2+1.1s

Solution for 180=0.05s^2+1.1s equation:

180=0.05s^2+1.1s

We move all terms to the left:

180-(0.05s^2+1.1s)=0

We get rid of parentheses

-0.05s^2-1.1s+180=0

a = -0.05; b = -1.1; c = +180;
Δ = b2-4ac
Δ = -1.12-4·(-0.05)·180
Δ = 37.21
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.1)-\sqrt{37.21}}{2*-0.05}=\frac{1.1-\sqrt{37.21}}{-0.1}
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.1)+\sqrt{37.21}}{2*-0.05}=\frac{1.1+\sqrt{37.21}}{-0.1}
$